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    Flare Systems

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    Warning Light Radiation Shield

    An aircraft warning light sits a few metres from a flare tip that burns purge gas continuously, for the whole life of the plant. The question is narrow and practical: how much of that small flame does the light actually see past its shield, and is the radiation it receives low enough for the fixture to survive. The geometry is the entire calculation, which is why it is drawn.

    Tip & purge

    Set the purge flow to 0 to use the heat release field instead.

    Flame

    The flame length comes from the API 521 correlation, computed separately and brought in here — the stack height tool on this site does it. The droop is practice, not standard: common rules give one or two tip diameters, capped at around 1.5 m.

    Light & shield

    Two points measured off the drawing, not a rule: the line of sight passes through the light and the edge of the shield. Any other construction would be an assumption invented here.

    Within the allowable

    0.85 kW/m²

    269 Btu/hr/ft² against an allowable of 1.58 kW/m². The light sees 27% of the flame.

    platform / datumtippurge flame 5.05 mshield edgeACWLD = 3.68 mseen 27% · K = 0.85 kW/m²
    The dashed line is the line of sight from the light over the shield edge. The lit part of the flame is the part the light actually sees; the radiation is computed on that part alone, from its centre. Move the shield edge and watch the visible fraction change — that is the whole design decision.
    Intermediate resultValueRelation
    Heat release3,813 kWQ = qv · LHV / 3.6
    Flame end, horizontal reach4,959 mm√(L² − droop²)
    Line of sight crosses flame axis at3,628 mmline intersection
    Fraction of flame in view0.268 clamped to 0 … 1
    Centre of the viewed flame4,294 / 3,074 mm (x / y)midpoint of the visible part
    Distance to the light3.68 mD = √(Δx² + Δy²)
    Atmospheric transmissivity0.941 τ = 0.79 · (100/RH)^(1/16) · (30.5/D)^(1/16)
    Radiation on the light0.848 kW/m²K = τ · F · frazione · Q / (4πD²)
    Radiation, imperial269 Btu/hr/ft²1 Btu/hr/ft² = 3.155 W/m²

    What this does not cover

    A two-dimensional section through one plane, with the flame as a straight line and a point source at its centre. It ignores wind, which moves the flame out of that plane and is the case that usually governs; it ignores reflected and re-radiated heat from the stack and the platform, convection from hot gas, and the flame from an actual relief event rather than the purge. The shield is treated as a straight edge. It is a screening calculation, not a verification, and carries no warranty.

    Need the real study?

    Send us the tip general arrangement and the platform layout and we will check the warning lights, the platforms and the access ways together, under wind, with the radiation contours behind them.

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